TSO MATH EIS:Homework Find the area of the triangle whose given 3 vertices EIS คณิต กับ ครูโซ่ ยอดหทัย รีศรีคำ

  Example :

my name’s Yodhathai reesrikom        secondary 6/2   No.8

My Question :    Find the area of the triangle whose vertices are  (-3, -5), (2, -5), and (-3, -1)

solution …………………….

…………………….

…………………….

…………………….

Answer       Area of the triangle whose vertices are  (-3, -5), (2, -5), and (-3, -1)   is…………………..

work

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  • น.ส. รัตนากร ใจสุข

    My name’s Miss.Rattanakorn Jaisook secondary 6/2 No.28

    My Question : Find the area of the triangle whose vertices are (-4, 5), (-2, -8) and (-10, -20)
    solution Area = 1/2 I(32+40-50) – (-10+80+80)I
    = 1/2 I22 – (150)I
    = 1/2 I-128I
    = 1/2*128
    Area = 64
    Answer Area of the triangle whose vertices are (-4, 5), (-2, -8) and (-10, -20) is 64

    • Siridet Kanaso

      My name’s siridet kankso
      secondary 6/2 No.1

      My Question : Find the area of
      the triangle

      whose vertices are (5,10), (5, 3) and (14,3)

      solution Area = 1/2
      I(15+15+140) – (50+42+15)I

      = 1/2 I170 – (-107)I

      = 1/2 I63I

      = 1/2*63

      Area = 31.5

      Answer
      Area of the triangle whose vertices are (5,10), (5, 3) and (14,3)is 31.5

  • น.ส. จณิสตา อัมพรมหา ม.6/2 เลขที่ 17

    My name’s Miss.Janissata Umphonmaha secondary 6/2 No.17
    My Question : Find the area of the triangle whose vertices are (-2, -3), (-4, -5) and (-6, 7)
    solution Area = 1/2 I(10+28+18) – (12+30-14)I
    = 1/2 I56 – (28)I
    = 1/2 I28I
    = 1/2*28
    Area = 14
    Answer Area of the triangle whose vertices are (-2, -3), (-4, -5) and (-6, 7) is 14

  • https://www.facebook.com/juggy.mummy วราภรณ์ ดีรัตน์

    My name’s Miss Waraphon Deerat Secondary 6/2 No.29

    My Question : Find the area of triangle whose vertices are
    (-2,-8),(-3,-9) and (-4,-10)

    Solution
    = 1/2 l(18+30+32)-(24+36+20)l
    = 1/2 (70 – 80)
    = 1/2 (-10)
    = -5

    Answer The area of triangle = -5

  • น.ส.ณัชญา สุวรรณโชติ

    My name’s natchaya suwannachote secondary 6/2 No.21
    My Question : Find the area of the triangle whose vertices are (-2, -5), (-20, -6), and (-4, -3)
    solution = 1/2 l(12+60+20) – (100+24+6)l
    = 1/2 l92-130l
    = 1/2 l-38l
    = 1/2*38
    = 19
    Answer Area of the triangle whose vertices are (-2, -5), (-20, -6), and (-4, -3) is 19

  • kasidit sanong

    My name’s Mr.Kasidit Sanong secondary 6/2 No.3

    My Question : Find the area of the triangle whose vertices are (-2,-8), (-6, -3) and (-12, -10)
    solution Area = 1/2 I(6+60+96) – (48+36+20)I
    = 1/2 I162 – (104)I
    = 1/2 I 58 I
    = 1/2*58
    Area = 29
    Answer Area of the triangle whose vertices are (-2,-8), (-6, -3) and (-12, -10) is 29

  • น.ส.ปนัดดา กิจสุวรรณ

    My name’s panadda kitsuwan secondary 6/2 No.38
    My Question : Find the area of the triangle whose vertices are (-1, -2), (2, 4), and (4, -2)
    solution = 1/2 l(-4-4-8) – (-4+16+2)l
    = 1/2 l16-(-14)l
    = 1/2 l-30l
    = 1/2*30
    = 15
    Answer Area of the triangle whose vertices are (1, -2), (2, 4), and (4, -2) is 15

  • Buffering J’Jao

    My name’s Watcharapong Zaekor secondary 6/2
    No.10

    My Question : Find the area of the triangle whose
    vertices are (10,10), (8,5 ), and (6, 5)

    solution = 1/2 l(50+40+54) – (50+30+80)l

    = 1/2 l144-160l

    = 1/2 l16l

    = 1/2*16

    = 8

    Answer Area of the triangle whose vertices are (10,10),
    (8,5 ), and (6,5) is 8

  • น.ส.ปนัดดา กิจสุวรรณ

    My name’s panadda kitsuwan secondary 6/2 No.38
    My Question : Find the area of the triangle whose vertices are (-1, -2), (2,4 ), and (4, -2)
    solution = 1/2 l(-4-4-8) – (-4+16+2)l
    = 1/2 l-16-(-14) l

    = 1/2 l-30l
    = 1/2*30
    = 15
    Answer Area of the triangle whose vertices are (-1, -2), (2, 4), and (4, -2) is 15

  • น.ส. อรพิณ อาจิณ

    My name’s Miss.Orapin Arjin secondary 6/2 No.31

    My
    Question : Find the area of the triangle whose vertices are
    (-5,-9),(-20
    ,2) and(- 14,-3)

    solution Area = 1/2 I(-10+60+126) – (180-28+15)I

    = 1/2 I176 – 167I

    = 1/2 I9I

    = 1/2*9

    Area = 4.5

    Answer Area of the triangle whose vertices are (-5,-9),(-20 ,2) and(- 14,-3) is
    4.5

  • Guest

    My
    name’s Nuttha Udom Secondary 6/2 No.20

    My Question: Find the area of the triangle whose vertices are

    (-7,-5), (-3,-2) and (-1,-1)

    Solution = 1/2 * I (14+3+5) – (15+2+7) I

    = 1/2 * I 22-6 I

    = 1/2 * 16

    = 8

    Answer Area of the triangle whose vertices are (-7,-5), (-3,-2) and
    (-1,-1) is 8

  • นางสาวณัฐฐา อุดม

    My
    name’s Nuttha Udom Secondary 6/2 No.20

    My Question: Find the area of the triangle whose vertices are

    (-7,-5), (-3,-2) and (-1,-1)

    Solution = 1/2 * I (14+3+5) – (15+2+7) I

    = 1/2 * I 22-6 I

    = 1/2 * 16

    = 8

    Answer Area of the triangle whose vertices are (-7,-5), (-3,-2) and
    (-1,-1) is 8

  • M’Mai Ungsima

    My name’s Miss.Ungsima Prachuimwongs secondary 6/2 No.33

    MyQuestion : Find the area of the triangle whose vertices are (-5,-4),(5,-3)and(2,-4)

    solution area = 1/2 I(15-20-18) – (-45-6+20)I

    =1/2 I-23+31I

    =1/2 I8I

    =1/2*8

    Area = 4

    Answer Area of the triangle whose vertices are (-5,-4),(5,-3)and(2,-4) is 4

  • Phasakorn Tongthumkit

    MyQuestion : Find the area of the triangle whose vertices are
    (2,3),(4,2) and(2,4)

    solution Area = 1/2 I(4+12+4) – (12+4+12)I

    = 1/2 I20-28I

    = 1/2 I-8I

    = 1/2*8

    Area = 4

    Answer Area of the triangle whose vertices are (2,3),(4 ,2) and(2,4) is
    4

  • C’Chalinee N’oon

    My name’s Miss. Chalinee Bumrurrai secondary 6/2 No.19

    My Question : Find the area of the triangle whose vertices are
    (1,3),(5,3) and(5,5)

    solution Area = 1/2 I(3+25+15) – (5+15+15)I

    = 1/2 I43 – 35I

    = 1/2 I8I

    = 1/2*8

    Area = 4

    Answer Area of the triangle whose vertices are(1,3),(5,3) and(5,5) is 4

  • Montira ‘Xaou

    My name’s Montira Hiamhan secondary 6/2 No.27

    My Question : Find the area of the triangle whose vertices are (5,8), (-1,-1), and (-3,4)

    Sol. Area of the triangle = 1/2 I (-5-4-24) – (-8+3+20) I

    =1/2 I -33 – 15 I

    =1/2 I -48 I

    =1/2 * 48

    =24

    Area of the triangle = 24

    Answer Area of the triangle whose vertices are (5,8), (-1,-1), and (-3,4) is 24

  • นายนพรุจ คำเขียว

    นายนพรุจ คำเขียว

    My Question : Find the area of the triangle whose vertices
    are (4,5), (10,4), and (-3,-7)

    Sol. Area of the triangle = 1/2 I (16-70-15) – (-28+12+50) I

    =1/2 I -69-34 I

    =1/2 I 103 I

    =1/2 * 103

    =51.5
    Area of the triangle = 51.5
    Answer Area of the triangle whose vertices are (4,5), (10,4), and (-3,-7) is 51.5

  • อัญชลร ตรีมหาโชค

    My name’s Miss.Anchalee Treemahachot secondary 6/2 No.34

    My Question : Find the area of the triangle whose vertices are (-15, -2), (-8, 1) and (-3, 7)

    solution Area = 1/2 I(-56+6-15) – (-3-105+16)I

    Area= 1/2 I-56 – (92)I

    = 1/2 I-61I

    = 1/2*61

    Area = 30.5

    Answer Area of the triangle whose vertices are (-15, -2), (-8, 1) and (-3, 7) is
    30.5

  • น.ส.รัตนากร ใจสุข

    My name’s Miss.Benjarat Moolsrikaew
    secondary
    6/2 No.26

    My Question : Find the area of the triangle
    whose vertices are (2, 5), (-4, -3) and (3, -2)

    solution Area = 1/2 I(-6+8+15) – (-20-9-4)I

    = 1/2 I17 – (-33)I

    = 1/2 I50I

    = 1/2*50

    Area = 25

    Answer Area of the triangle whose vertices are (2, 5), (-4, -3) and (3, -2) is
    25

  • นาย กิตตินันท์ อาริน

    My name’s Mr.Kittinun Arin secondary 6/2 No.4

    My Question : Find the area of the triangle whose vertices are (4,5), (21, 2) and (6,9)

    solution Area = 1/2 I(8+189+30) – (105+12+36)I

    = 1/2 I227 – (153)I

    = 1/2 I74I

    = 1/2*74

    Area = 37

    Answer Area of the triangle whose vertices are (4,5), (21, 2) and (6,9) is 37

  • นาย กิตตินันท์ อาริน

    My name’s Mr.Kittinun Arin secondary 6/2 No.4

    My Question : Find the area of the triangle whose vertices are (4,5), (21, 2) and (6,9)

    solution Area = 1/2 I(8+189+30) – (105+12+36)I

    = 1/2 I227 – (153)I

    = 1/2 I74I

    = 1/2*74

    Area = 37

    Answer Area of the triangle whose vertices are (4,5), (21, 2) and (6,9) is 37

  • นาย สุพิฌา วิทนาลัย

    My name’s Mr.Supicha Wittayalai secondary 6/2 No.12

    My Question : Find the area of the triangle whose vertices are (-2,-8), (-4, -5) and (-1,-1)

    solution Area = 1/2 I(8+10+4) – (2+32+5)I

    = 1/2 I22 – (39)I

    = 1/2 I-17I

    = 1/2*17

    Area = 8.5

    Answer Area of the triangle whose vertices are (-2,-8), (-4, -5) and (-1,-1) is 8.5

  • นาย ภัทรวิทรย์ จริตซื่อ

    My name’s Mr.Phattarawit Jaritser secondary 6/2 No.8

    My Question : Find the area of the triangle
    whose vertices are (1,-4), (8, 10) and (5,-5)

    solution Area = 1/2 I(-5+50-32) – (-20-40+10)I

    = 1/2 I13 – (-50)I

    = 1/2 I63I

    = 1/2*63

    Area = 31.5

    Answer Area of the triangle whose vertices are (1,-4), (8, 10) and (5,-5) is 31.5

  • น.ส.นมัสสิการ สุวรรณโชติ

    My name’s Miss.Namassikarn Suwanachote secondary 6/2 No.24

    My Question : Find the area of the triangle
    whose vertices are (-10,8), (-12, 2) and (14,3)

    solution Area = 1/2 I(-96-36-30) – (-20-36-112)I

    = 1/2 I192 – (-168)I

    = 1/2 I360I

    = 1/2*360

    Area = 180

    Answer Area of the triangle whose vertices are (-10,8), (-12, 2) and (14,3) is 180

  • อริสา เกิดมณี

    My name’s Miss.Arisa Kerdmanee secondary 6/2 No.32

    My Question : Find the area of the triangle whose vertices are (-15, -2), (-8, 1) and (-3, 7)

    solution Area = 1/2 I(-56+6-15) – (-3-105+16)I

    = 1/2 I-56 – (92)I

    = 1/2 I-61I

    = 1/2*61

    Area = 30.5

    Answer Area of the triangle whose vertices are (-15, -2), (-8, 1) and (-3, 7) is
    30.5

  • อริสา เกิดมณี

    My name’s Miss.ArisaKerdmanee secondary6/2 No.32

    My Question : Find the area of the triangle whose vertices are (3,3), (4, 3) and (5, 2)

    solution Area = 1/2 I(9+8+10) – (12+15+6)I

    = 1/2 I32+32I

    = 1/2 I0I

    = 1/2*0

    Area = 0

    Answer Area of the triangle whose vertices are (3,3), (4, 3) and (5, 2) is 0

  • Na’k Nea

    Miss Daranee Somkit m.6/2 no.22

    My Question : Find the area of the triangle whose vertices are (6, 2), (6,8) and (4,8)

    solution Area = 1/2 I(48-48-8) – (12-32-48)I

    = 1/2 I(-8) – (-68)I

    = 1/2 I-76I

    = 1/2 I76I

    = 1/2*76

    Area = 38

    Answer Area of the triangle whose vertices are (6,2), (6,8) and (4,8) is 38

  • Sirinard Budsamalee Class6/2

    Ms.Sirinard Budsamalee Class6/2 No.39

    My Question : Find the area of the triangle whose vertices
    are (-14, 5), (3,-10) and (0,8)

    solution Area = 1/2 I(-140+24+0) – (15-0-(-112))I

    = 1/2 I164 – 97I

    = 1/2 I67I

    = 1/2 I67I

    = 1/2*67

    Area = 33.5

    Answer Area of the triangle whose vertices are (-14,2),
    (3,-10) and (0,8) is 33.5

  • D’Domy Anuwat

    My name’s Anuwat Meebun secondary 6/2 No.14

    My Question : Find the area of the triangle whose vertices are (-3, 6), (2, -5)
    and (5, -4)

    solution

    Area =1/2 I(15-8+30) – (12-25+12)I

    = 1/2 I37 – (-1)I

    = 1/2 I38I

    = 1/2*38

    Area = 19

    Answer Area of the triangle whose vertices are (-3, 6), (2, -5) and

    (5, -4) is 19

  • นาย นพรุจ อ้างสกุล

    My name’s Mr.Nopparut Angsakul secondary 6/2 No.15

    My Question : Find the area of the triangle whose vertices are (10, 8), (5, 2) and (4, 1)

    solution
    Area = 1/2 I(20+5+32) – (40+8+10)I

    = 1/2 I57- (58)I

    = 1/2 I1I

    = 1/2*1

    Area = 0.5

    Answer Area of the triangle whose vertices are (10, 8), (5, 2) and (4, 1) is
    0.5

  • นาย นพรุจ อ้างสกุล

    My name’s Mr.Kasem sawaneya secondary 6/2 No.5

    My Question : Find the area of the triangle whose vertices are (15, 2), (5, 3) and (1, 4)
    solution Area = 1/2 I(45+20+2) – (10+3+60)I

    Area = 1/2 I67- (73)I
    = 1/2 I6I
    = 1/2*6
    Area = 3
    Answer Area of the triangle whose vertices are (15, 2), (5, 3) and (1, 4) is 3

  • M’Mai Ungsima

    Ms.THIRISARA CHALONG Class6/2 No.23

    My Question : Find the area of the triangle whose vertices
    are (-3.-4) (2.-5)and (-1.6)
    solution Area = I(4-12+15)-(18+5-8)I
    =1/2* I(23-15)I

    =1/2* I8I

    =4

    Area = 4

    Answer Area of the triangle whose vertices are (-3.-4) (2.-5)and (-1.6) is 4

    ธีริศรา ฝากส่งค้ะ มันล็อกอินไม่ได้ค้ะ

  • น.ส.ปรียา กระโห้ทอง

    My name’s Miss.Preeya Kahotong secondary 6/2 No.37

    My Question : Find the area of the triangle whose vertices are (10, -5), (-4, -8) and (-11, 2)

    solution
    Area = 1/2 I(-80-8+55) – (20+88+20)I
    = 1/2 I-33- (128)I
    = 1/2 I-161I
    = 1/2*161
    Area = 80.5
    Answer Area of the triangle whose vertices are (10, -5), (-4, -8) and (-11, 2) is
    80.5

  • jirapa kawjun m.6/2

    My name’s Jirapa Kawjun secondary 6/2 No.18

    My Question : Find the area of the triangle whose vertices are
    (15,8), (5,12),

    and (2,4)

    Sol.

    Area = 1/2 I (180+20+16) – (40+124+60) I

    =1/2 I 216 – 124 I

    =1/2 I 90 I

    =1/2 * 90

    =45

    Area = 45

  • Siridet Kanaso

    My name’s siridet kankso
    secondary 6/2 No.1

    My Question : Find the area of
    the triangle

    whose vertices are (5,10), (5, 3) and (14,3)

    solution Area = 1/2
    I(15+15+140) – (50+42+15)I

    = 1/2 I170 – (-107)I

    = 1/2 I63I

    = 1/2*63

    Area = 31.5

    Answer
    Area of the triangle whose vertices are (5,10), (5, 3) and (14,3)is 31.5

  • Siridet Kanaso

    Write the coordinate of the point P when it divides the line AB
    internally in the ratio of 3:4 when A(x-1, y2) and B(x2, y5)

    X = nx1+my2/m+n

    = 3(2) + 4(-1)/4+3

    = 6 – 4/7

    = 2/7

    = 0.285

    Y =nx2+my2/m+n

    = 3(5) + 4(2)/7

    = 15 + 8/7

    = 23/7

    = 3.28

  • นายวินิจ มีบุญ

    My name’s Winit Meebun secondary 6/2 No.11

    My Question : Find the area of the triangle whose vertices are
    (8,3), (2,1),and (3,4)

    Sol.
    =1/2*I(8-8-9) – (32-3-6)I
    =1/2*I-9-23I
    =1/2*I-32I
    =1/2*32
    =16